Answer
$-\frac{27y^{12}}{8x^{\frac{1}{2}}}$
Work Step by Step
We are given
$(-\frac{2x^{\frac{1}{6}}}{3y^4})^{-3}$
$=(-\frac{3y^4}{2x^{\frac{1}{6}}})^{3}$
$=-\frac{27y^{12}}{8x^{\frac{1}{2}}}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 443: 44
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