Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 443: 43



Work Step by Step

You have (-$\frac{7x^3{^/}{^2}}{5y^4}$$)^{-2}$.Simplify the expression: $\frac{-7^-{^2}x^-{^3}}{5^-{^2}y^-{^8}}$ -multiply every value in the parentheses by -2- $\frac{5^2y^8}{-7^2x^3}$ -apply exponent rule $a^{-y}$=$\frac{1}{a^y}$- =$\frac{25y^8}{49x^3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.