## Algebra 1: Common Core (15th Edition)

4 $\times$ $10^{-5}$
You have $\frac{3.6 *10^-{^1}{^0}}{9 * 10^-{^6}}$.Simplify: $\frac{3.6 *10^-{^1}{^0}}{9 * 10^-{^6}}$ -subtract the exponents- $10^{-10-(-6)}$=$10^{-4}$ $\frac{3.6}{9}$ $\times$ $10^{-4}$ -divide the terms- 0.4 $\times$ $10^{-4}$ -write the number in the correct format by moving the decimal over and subtracting -1 from the exponent- =4 $\times$ $10^{-5}$