Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-3 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 51



Work Step by Step

You are given ($m^{2}$$n^{3}$$)^{?}$=$\frac{1}{m^6n^9}$.Solve for the blank: ($m^{2}$$)^{?}$ ($n^{3}$$)^{?}$=$\frac{1}{m^6n^9}$ -multiply each term outside the term to the power ?- $m^{2?}$$n^{3?}$=$\frac{1}{m^6n^9}$ -use power to power rule- $\frac{1}{m^6}$=$m^{-6}$ and $\frac{1}{n^9}$=$n^{-9}$ -apply exponent rule $\frac{1}{a^b}$=$a^{-b}$- 2?=-6 and 3?=-9 -we need to have common base exponents which equal each other- ?=-3 -isolate the blank- =($m^{2}$$n^{3}$$)^{-3}$=$\frac{1}{m^6n^9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.