Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-3 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 31



Work Step by Step

You are given 4$j^{2}$$k^{6}$(2$j^{11}$$)^{3}$$k^{5}$.Simplify: 4$j^{2}$$k^{6}$2$^3$($j^{11{\times}3}$)$k^{5}$ -Raise the terms in the parentheses to 3- 4$j^{2}$$k^{6}$2$^3$($j^{33}$)$k^{5}$ -add the exponents of like terms since you are multiplying - 4$\times$$2^{3}$$j^{2+33}$$k^{5+6}$ The simplified expression is 32$j^{35}$$k^{11}$
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