## Algebra 1: Common Core (15th Edition)

$(m^{-36})^{\frac{1}{3}} = m^{-12}$
When we raise a power to a power, we multiply the powers together and keep the base. We have to think what number multiplied with $\frac{1}{3}$ will give us $-12$: $\frac{1}{3}x = -12$ Divide each side by $\frac{1}{3}$ to solve: $x = -36$ Let's rewrite the equation: $(m^{-36})^{\frac{1}{3}} = m^{-12}$