Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - Chapter Test - Page 411: 8



Work Step by Step

Given: $2x + 5y = 20$ $3x - 10y = 37$ Multiply both sides of the first equation with 2: $4x + 10y = 40$ $3x - 10y = 37$ Let's add the two equations to eliminate the y-terms. We get: $7x=77$ $x=11$ Now let's substitute this value of x into the first equation in order to find the value of y. $2(11) + 5y = 20$ $5y=-2$ $y=\frac{-2}{5}$ So, our solution is $(11,\frac{-2}{5})$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.