Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 384: 52

Answer

(5,-3)

Work Step by Step

You have the equations:x+2y=-1 and 3x-5y=30. Multiply the first equation by -3 in order to eliminate the x variable: -3(x+2y=-1) -3x-6y=3 Combine the equations: 3x-5y=30 -3x-6y=3 -11y=33 -divide both sides by -11- y=-3 Plug in y=-3 into one of the equations: x+2(-3)=-1 -distribute- x-6=-1 -add 6 to both sides- x=5 Check your work by plugging in x=5 and y=-3 into one of the equations: 3(5)-5(-3)=30 15+15=30 30=30 The solution is (5,-3)
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