Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 384: 44


Yes. It is possible to score exactly 100 points with all seven darts landing on the board.

Work Step by Step

This problem is a simple system of equations. This can be set up as: Legend: x=19 and y=8, in terms of the values on the dartboard. 1st: $x+y=7$ 2nd: $19x+8y=100$. Using multiplication to achieve the same coefficients for y, we can multiply the 1st equation by 8. This will give us an equation of $8x+8y= 56$. We can then subtract the 2nd equation from this new equation. $8x+8y= 56$ - $19x+8y=100$ This will result in $-11x= 44$. Dividing both sides by -11 will give a value of $x=4$. Substituting x=4 into the first equation will allow us to solve for y. $4+y=7$ which simplifies to $y=3$ This solutions means that 100 can be scored with 4 19's and 3 8's.
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