## Algebra 1: Common Core (15th Edition)

$x=7$ $y=\frac{7}{2}$
We are given: $y=\frac{1}{2}x$ $2y+3x=28$ Move $\frac{1}{2}x$ to the left side in the first equation: $y-\frac{1}{2}x=0$ Multiply both sides by $-2$: $-2y+x=0$ $2y+3x=28$ ________________ $4x=28$ $x=7$ Solve for $y$: $y=\frac{1}{2}x=\frac{1}{2}(7)=\frac{7}{2}$