## Algebra 1: Common Core (15th Edition)

$2x-3y=-2$
We first multiply both sides of the equation by 3 to cancel out the fractions and give us integers. Thus, we obtain: $3y+6=2(x+4)$ We now simplify using the distributive property: $3y+6=2x+8$ In order to write the equation in standard form, we must get y and x on the same side of the equation: $-2x+3y+6=8 \\\\ -2x+3y=2 \\\\ 2x-3y=-2$ We want this equation to be in standard form using integers, but both x and y are already being multiplied by integers.