#### Answer

6

#### Work Step by Step

Use the formula of permutation: $_{n}$P$_{r}$=$\frac{n!}{(n-r)!}$. Plug in 3 for N and 3 for R:
$_{n}$P$_{r}$=$\frac{n!}{(n-r)!}$
$_{3}$P$_{3}$=$\frac{3!}{(3-3)!}$ -simplify-
$_{3}$P$_{3}$=$\frac{3!}{0!}$ -write using factorial-
$_{3}$P$_{3}$=$\frac{3*2*1}{1}$ -simplify-
$_{3}$P$_{3}$=6