Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 767: 46


We need 45 line segments to join each point for figure 2.

Work Step by Step

There are 10 points for figure 2. We will now use combinations. First of all, we need to find the number of combinations of 10 points chosen 2 at a time. Find $10C_{2}$ Write using factorials: $10C_{2}=\frac{10 !}{2!(10-2)!=\frac{10!}{2!8!}}$ Simplify: $10C_{2}=45$ Therefore, we need 45 line segments to join each point.
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