Answer
The answer is $3d-7-\frac{8}{d+3}$
Work Step by Step
$(3d^2+2d-29) \div (d+3)$
$3d$
_________________________
$d+3) 3d^2+2d-29$
$-3d^2-9d$
_________________________
$-7d-29$
$7d+21$
_________________________
$-8$
The answer is $3d-7-\frac{8}{d+3}$
