Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Chapter Review - Page 716: 13



Work Step by Step

$\frac{x^2+13x+40}{x-7}\div\frac{x+8}{x^2-49}$ $=\frac{x^2+5x+8x+40}{x-7}\div\frac{x+8}{(x-7)(x+7)}$ $=\frac{(x+8)(x+5)}{x-7}\times\frac{(x-7)(x+7)}{x+8}$ $=\frac{(x+8)(x+5)(x-7)(x+7)}{(x-7)(x+8)}$ $=(x+5)(x+7)$
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