Answer
$\frac{h^{2}+h+1}{2t^{2}-7}$
Work Step by Step
Given : $\frac{h^{2}+1}{2t^{2}-7} + \frac{h}{2t^{2}-7}$
This becomes : $\frac{h^{2}+1+h}{2t^{2}-7}$
(Since they both have the same denominator)
$= \frac{h^{2}+h+1}{2t^{2}-7}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-4 Adding and Subtracting Rational Expressions - Practice and Problem-Solving Exercises - Page 688: 38
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