Answer
$\frac{5t+5-4t^{2}}{t^{2}(t+1)}$
Work Step by Step
Given : $\frac{5}{t^{2}} - \frac{4}{t+1}$
This becomes : $\frac{5(t+1)}{t^{2}(t+1)} - \frac{4t^{2}}{t^{2}(t+1)}$
(Finding the least common denominator)
$= \frac{5(t+1)-4t^{2}}{t^{2}(t+1)}= \frac{5t+5-4t^{2}}{t^{2}(t+1)}$
