## Algebra 1: Common Core (15th Edition)

$\frac{-y^2+2y+2}{3y+1}$
$\frac{y^2+2y-1}{3y+1}-\frac{2y^2-3}{3y+1}$ Add: $=\frac{y^2+2y-1-2y^2+3}{3y+1}$ Simplify: $=\frac{-y^2+2y+2}{3y+1}$ The solution is $\frac{-y^2+2y+2}{3y+1}$.