## Algebra 1: Common Core (15th Edition)

The answer is $b+6+\frac{25}{2b+4}$.
$(49+16b+2b^2) \div (2b+4)$ $=(2b^2+16b+49) \div (2b+4)$ $b+6$ _________________________ $2b+4)2b^2+16b+49$ $-2b^2-4b$ _________________________ $12b+49$ $-12b-24$ _________________________ $25$ The answer is $b+6+\frac{25}{2b+4}$.