Answer
The answer is $4q^2+2q+\frac{3}{2}+\frac{9}{2q-2}$.
Work Step by Step
$(6-q+8q^3-4q^2) \div (2q-2)$
$=(8q^3-4q^2-q+6) \div (2q-2)$
$4q^2+2q+\frac{3}{2}$
_________________________
$2q-2)8q^3-4q^2-q+6$
$-8q^3+8q^2$
_________________________
$4q^2-q$
$-4q^2+4q$
_________________________
$3q+6$
$-3q+3$
_________________________
$9$
The answer is $4q^2+2q+\frac{3}{2}+\frac{9}{2q-2}$.
