Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 681: 32


$3x^3 -7x^2+\frac{41x^2}{2x+6}$

Work Step by Step

$(6x^4+4x^3-x^2) \div (6+2x)$ $=(6x^4+4x^3-x^2) \div (2x+6)$ $3x^3 -7x^2$ _________________________ $2x+6)6x^4+4x^3-x^2$ $-6x^4-18x^3$ _________________________ $-14x^3-x^2$ $14x^3+42x^2$ _________________________ $41x^2$ The answer is $3x^3 -7x^2+\frac{41x^2}{2x+6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.