## Algebra 1: Common Core (15th Edition)

$t+3$
$\frac{t^2+5t+6}{t-3}.\frac{t^2-2t-3}{t^2+3t+2}$ Factor: $=\frac{(t+2)(t+3)}{t-3}.\frac{(t-3)(t+1)}{(t+1)(t+2)}$ Divide out common factors $=t+3$