Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 675: 56

Answer

$\frac{x-5}{x}, with$ $x\ne0$

Work Step by Step

Given : $(\frac{x^{2}+x-6}{x^{2}-4x}) \times (\frac{x^{2}+x-20}{x^{2}+10x+25}) =\frac{(x-5)(x+5)}{x(x-4)} \times \frac{(x-4)(x+5)}{(x+5)(x+5)}=\frac{x-5}{x}$ (After dividing out the common factors (x-4) and (x+5))
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