Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 675: 55


$\frac{x-2}{x-3}, with$ $x\ne3$

Work Step by Step

Given : $\frac{x^{2}+x-6}{x^{2}-x-6} \div \frac{x^{2}+5x+6}{x^{2}+4x+4}=\frac{(x+3)(x-2)}{(x-3)(x+2)} \times \frac{(x+2)(x+2)}{(x+2)(x+3)}$ This becomes : $\frac{x-2}{x-3}$ (After dividing out the common factors (x+2) and (x+3))
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