## Algebra 1: Common Core (15th Edition)

The hypotenuse is 50 and the leg is 14. To find the other leg plug in a and c into the Pythagorean formula $a^{2}$ + $b^{2}$= $c^{2}$ --> $14^{2}$ + $b^{2}$= $50^{2}$: $14^{2}$ + $b^{2}$= $50^{2}$ -simplify the exponent- 196 + $b^{2}$ =2500 - subtract 196 from both sides- $b^{2}$=2304 -find the square root of 2304 to solve for b- b=48 B is 48.