Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 631: 69

Answer

15 $\sqrt 6$

Work Step by Step

Simplify 3$\sqrt {150}$: 3 $\sqrt {25*6}$ -factor out the term 150- 3$\sqrt {25}$ $\times$ $\sqrt 6$ -simplify- 3$\times$ 5 $\sqrt 6$ -multiply- =15 $\sqrt 6$
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