Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 631: 68

Answer

6$\sqrt 3$

Work Step by Step

Simplify $\sqrt {108}$: $\sqrt {108}$ -factor out the term- $\sqrt {36*3}$ -simplify each square root- 6 $\times$ $\sqrt 3$ -simplify- =6$\sqrt 3$
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