Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 631: 65

Answer

(H) $4.41\times 10^5\;m^2$.

Work Step by Step

Height of the triangle $h=4.2\times 10^2 \;m$. Base of the triangle $b=2.1\times 10^3\; m$. Area of the triangle $A=\frac{1}{2}bh$. Substitute both values. $A=\frac{1}{2}(2.1\times 10^3\;m)(4.2\times 10^2\;m)$ Simplify. $A=(2.1\times 10^3\;m)(2.1\times 10^2\;m)$ $A=4.41\times 10^5\;m^2$. Hence, the correct option is (H) $ A=4.41\times 10^5\;m^2$.
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