## Algebra 1: Common Core (15th Edition)

We follow the instructions and plug 4 in for b, 2 in for a, and 3 in for c. In this problem, we use the order of operations to simplify in the correct order. According to the order of operations, we simplify inside of parentheses, then we simplify powers, then we multiply and divide, and finally, we add and subtract. When we do this, we find: $(2(2))^{2}(4) - 2 \times (3^{2}) = (4^{2})(4)- 2 \times 9 = 16(4) -18 = 64-18=46$