## Algebra 1: Common Core (15th Edition)

$4^{2}-5\times(2+1)=1$
$4^{2}-5\times(2+1)=1$ Solve this equation by following the steps of PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). 1. PEMDAS tells us to solve the parenthesis in the equation first. $(2+1)=3$. Now the equation looks like this: $4^{2}-5\times3=1$. 2. The next step is to solve the exponent. $4^{2}= 16$. This simplifies the equation to $16-5\times3=1$. 3. Now we perform multiplication. $5\times3=15$, further simplifying the equation to $16-15=1$. 4. There is no division or addition in the equation, so the last step is subtraction. $16-15=1$, which makes $1=1$. By using PEMDAS, we were able to successfully solve the left side of the equation, proving it is equal to the right side of the equation.