Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - 1-2 Order of Operations and Evaluating Expressions - Practice and Problem-Solving Exercises: 57

Answer

$(16-4)\div2+3=9$

Work Step by Step

$(16-4)\div2+3=9$ Use PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction) to solve the left side of the equation. 1. The first step of PEMDAS is to solve the parenthesis. $(16-4)=12$, simplifying the equation to $12\div2+3=9$. 2. Exponents and multiplication do not apply in this problem, so our next step is division. $12\div2=6$. Now our equation reads $6+3=9$. 3. The last step in this equation is addition. Since $6+3=9$, $9=9$, making the equation true. Thus, the expression we found is correct.
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