Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - 1-2 Order of Operations and Evaluating Expressions - Practice and Problem-Solving Exercises: 32

Answer

$0$

Work Step by Step

Substituting $s=4$ and $t=8$, the given expression, $ 2s^2-t^3\div16 ,$ evaluates to \begin{array}{l}\require{cancel} 2(4)^2-(8)^3\div16 \\\\= 2(16)-512\div16 \\\\= 32-512\div16 \\\\= 32-32 \\\\= 0 .\end{array}
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