## Algebra 1: Common Core (15th Edition)

The problem states to "evaluate each expression for s=4 and t=8," so we first plug in s=4 and t=8. This gives us: $(2*4)^{2}*8$. We first consider what is inside the parenthesis, multiplying 2 by 4 to get 8. We then consider exponents, raising 8 to the second power to get 64. Finally, we multiply 64 by 8 to get 512.