## Algebra 1: Common Core (15th Edition)

The problem states to "evaluate each expression for s=4 and t=8," so we first plug in s=4 and t=8. This gives us: $(8+4)^{3}$. 8+4 is in parenthesis, so we consider it first, finding that 8 plus 4 is 12. We plug this in to obtain: $(12)^{3}=1728.$