Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 4 - Section 4.1 - Divisibility and Modular Arithmetic - Exercises - Page 244: 2

Answer

If $a$ is an integer other than 0, then a) 1 divides $a$ b) $a$ divides 0

Work Step by Step

Let $a$ be an integer other than 0. For proof of a), consider that 1 divides $a$ if there is an integer $c$ such that $a=\frac{1}{c}$. There is indeed such a $c$, and it is the multiplicative inverse of $a$, in fact. Now, to prove b). $a$ divides 0 because $c=0$ is an integer s.t. $a\cdot c=0$.
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