Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 2 - Section 2.6 - Matrices - Exercises - Page 184: 18

Answer

Yes they are inverses of each other.

Work Step by Step

Multiply the two matrices together. If their product equals to the identity matrix, then they are inverses of each other. $\begin{array}{l} \left[ {\begin{array}{*{20}{c}} 2&3&{ - 1}\\ 1&2&1\\ { - 1}&{ - 1}&3 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} 7&{ - 8}&5\\ { - 4}&5&{ - 3}\\ 1&{ - 1}&1 \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} {2(7) + 3( - 4) + ( - 1)(1)}&{2( - 8) + 3(5) + ( - 1)( - 1)}&{2(5) + 3( - 3) + ( - 1)(1)}\\ {1(7) + 2( - 4) + 1(1)}&{1( - 8) + 2(5) + 1( - 1)}&{1(5) + 2( - 3) + 1(1)}\\ { - 1(7) + ( - 1)( - 4) + 3(1)}&{ - 1( - 8) + ( - 1)5 + 3( - 1)}&{ - 1(5) + ( - 1)( - 3) + 3(1)} \end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}} 1&0&0\\ 0&1&0\\ 0&0&1 \end{array}} \right] \end{array}$
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