Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 18 - Electrical Properties - Questions and Problems - Page 779: 18.15


σ = 6.67 x $10^{6}$ $(Ω-m)^{-1}$ (Answers may slightly vary.)

Work Step by Step

Given: Tensile strength of Cu-Ni = 275 MPa (40,000psi) Required: Electrical conductivity of Cu-Ni Solution: From Figure 7.16a, the composition of an alloy having 275 MPa is about 10 wt% Ni. From Figure 18.9, the resistivity of this composition is about 15 x $10^{-8}$ Ω-m As conductivity is the reciprocal of resistivity (Equation 18.4), σ = $\frac{1}{p}$ = $\frac{1}{15 \times10^{-8} Ω-m}$ σ = 6.67 x $10^{6}$ $(Ω-m)^{-1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.