## Materials Science and Engineering: An Introduction

t= 3.4 $\times 10^{-4}$ s
Given: l = 25 mm $v_{d}$ = 72.5 $\frac{m}{s}$ Required: The time, t, required to traverse the given length Solution: t= $\frac{l}{v_{d}}$ = $\frac{25 \times 10^{-3}m}{72.5 \frac{m}{s}}$ = 3.4 $\times 10^{-4}$ s