Answer
$ µ_{e}$ = 5.57 x $10^{-3}$ $\frac{m^{2}}{Vs}$
Work Step by Step
Required:
electron mobility, $ µ_{e}$
Solution:
Using Equation 18.8,
$ µ_{e}$ = $\frac{σ}{n|e|}$ = $\frac{6.8 \times 10^{7} (Ωm)^{-1}}{(7.62 \times 10^{28} m^{-3})(1.602 \times 10^{-19}C)}$
$ µ_{e}$ = 5.57 x $10^{-3}$ $\frac{m^{2}}{Vs}$
