Answer
$\bf {F=8,316,970\text { lbf}}$
Work Step by Step
Given:
Storage capacity of water tower, $V=1\times 10^6~\text {gal}$.
Density of water, $\rho=62.4~\text {lb/ft}^3$.
Local acceleration due to gravity, $g=32.1~\text {ft/s}^2$
To Find:
Force in lbf.
Find the mass of the water neglecting the weight of the tower.
$m=\rho \times V$
$=62.4\left (\dfrac {lb}{ft^3}\right )1\times 10^6\text (gal)\times \dfrac {0.1337ft^3}{gal}$
$m=8,342,880 \text { lb}$
Find the force that must support the water tower.
$F=mg\\
=8342880 \text { (lb)}\times 32.1\text { (ft/s}^2)\left |\dfrac {\text {lbf}}{\text {32.2 lb.ft/s}^2}\right |\\
\bf {F=8,316,970\text { lbf}}$
