Answer
(a) The specific volume is volume per unit mass and can be determined from the total volume
and the mass of the liquid
v = V/m = 62.6 $in^{3}$/2 lb)( 1 $ft^{3}$/ 1728 $in^{3}$) = 0.0181 $ft^{3}$/lb.
(b) Density is the reciprocal of specific volume. Thus,
rho=1/(specific volume) = 1/ ( 0.0181 $ft^{3}$/lb ) = 55.2 lb/$ft^{3}$.
Work Step by Step
(a) The specific volume is volume per unit mass and can be determined from the total volume
and the mass of the liquid
v = V/m = 62.6 $in^{3}$/2 lb)( 1 $ft^{3}$/ 1728 $in^{3}$) = 0.0181 $ft^{3}$/lb.
(b) Density is the reciprocal of specific volume. Thus,
rho=1/(specific volume) = 1/ ( 0.0181 $ft^{3}$/lb ) = 55.2 lb/$ft^{3}$.
