Answer
$\begin{aligned} & M_B=90.6 \mathrm{lb} \cdot \mathrm{ft} \\ & M_C=141 \mathrm{lb} \cdot \mathrm{ft}\end{aligned}$
Work Step by Step
$\begin{aligned} & \left.↺+M_B=40 \cos 25^{\circ}(2.5)=90.6 \mathrm{lb} \cdot \mathrm{ft}\right) \\ & \left.↺+M_C=50 \cos 30^{\circ}(3.25)=141 \mathrm{lb} \cdot \mathrm{ft}\right)\end{aligned}$