Answer
$$
\left.M_A=195 \mathrm{lb} \cdot \mathrm{ft}\right)↺
$$
Work Step by Step
$$
\begin{aligned}
↺+M_A & =30 \cos 25^{\circ}(2.5)+45 \cos 30^{\circ}(3.25) \\
& =195 \mathrm{lb} \cdot \mathrm{ft}↺
\end{aligned}
$$
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 4 - Force System Resultants - Section 4.4 - Principle of Moments - Problems - Page 138: 10
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