Answer
$$
\begin{aligned}
& M_P=341 \text { in. } \cdot \mathrm{lb} (Counterclockwise)\\
& M_F=403 \mathrm{in.} \cdot \mathrm{lb} (Clockwise)
\end{aligned}
$$
Work Step by Step
$$
\begin{aligned}
& C+M_P=25\left(14 \cos 20^{\circ}+1.5 \sin 20^{\circ}\right)=341 \text { in } \cdot \mathrm{lb}(\text { Counterclockwise) } \\
& C+M_F=155 \sin 60^{\circ}(3)=403 \mathrm{in} \cdot \mathrm{lb}(\text { Clockwise })
\end{aligned}
$$
Since $M_F>M_P, \quad P=25 \mathrm{lb}$ It is not sufficient to pull out the nail.
