## Engineering Mechanics: Statics & Dynamics (14th Edition)

$v_{0}$= 12$\frac{ft}{s}$ $s_{0}$= 0 m t = 10 s a = -2$\frac{ft}{s^{2}}$ Using the kinematic equations, we have: x = $x_{0} + v_{0}t + \frac{1}{2}at^{2}$ s = $(0) + (12)(10) +\frac{1}{2}(-2)(10^{2})$ s = 120 -100 s = 20 ft