Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 12 - Kinematics of a Particle - Section 12.2 - Rectilinear Kinematics: Continuous Motion - Problems - Page 17: 2

Answer

s = 20 ft

Work Step by Step

$v_{0}$= 12$\frac{ft}{s}$ $s_{0}$= 0 m t = 10 s a = -2$\frac{ft}{s^{2}}$ Using the kinematic equations, we have: x = $x_{0} + v_{0}t + \frac{1}{2}at^{2}$ s = $(0) + (12)(10) +\frac{1}{2}(-2)(10^{2}) $ s = 120 -100 s = 20 ft
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