## Engineering Mechanics: Statics & Dynamics (14th Edition)

$t=30$s $s=792$m
We solve for time as follows: $v=v_1+a_ct$ $120=70+6000t$ $t=8.33\times10^{-3}$ hr = $30$ s Next, we solve for distance: $v^2=v_1^2+2a_c(s-s_1)$ $120^2=70^2+2(6000)(s-0)$ $s=0.792$ km $= 792$ m