Chapter 12 - Kinematics of a Particle - Section 12.2 - Rectilinear Kinematics: Continuous Motion - Problems - Page 17: 13

Normal: $d=517$ ft Drunk: $d = 616$ ft

Normal: Distance moved before reacting: $d'=v_0t=44(0.75)=33$ ft $v^2=v_0^2+2a_c(d-d')$ $0^2=44^2+2(-2)(d-33)$ $d=517$ ft Drunk: Distance moved before reacting: $d'=v_0t=44(3)=132$ ft $v^2=v_0^2+2a_c(d-d')$ $0^2=44^2+2(-2)(d-132)$ $d=616$ ft