Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.2 - Problems - Circuits, Currents, and Voltages - Page 35: P1.18


$ -1.92 \times 10^{-17}J$

Work Step by Step

We use the equation for the energy of the electron to find: $w = vq$ Where v is the voltage and q is the charge. Substituting the charge of an electron for q and the given voltage for v, we obtain: $w = 120 \times -1.6 \times 10^{-19}=-1.92 \times 10^{-17}J$ The electron goes from the negative to the positive, so the electron is going from lower to higher potential. Thus, it follows that $\underline{the \ electron \ gains \ energy.}$
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