## Electrical Engineering: Principles & Applications (6th Edition)

We know the following equation for charge: $Q = \int_{t_0}^{t} idt$ Using substitution, we obtain: $Q = \int_{0}^{.01} 5sin(200 \pi t)dt \\ Q = 0$ We now solve for the charge from 0 to 15 milliseconds using the same process: $Q = \int_{0}^{.015} 5sin(200 \pi t)dt$ Using a calculator to evaluate this integral, we find: $Q = 15.9\ mC$