Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.2 - Problems - Circuits, Currents, and Voltages: P1.11


Charge during interval: $$360,000C$$ and energy delivered: $$3.6\times10^{6} J$$

Work Step by Step

Current times time equals charge. $10A\times10hr\times\frac{60min}{hr}\times\frac{60s}{min}$ Power is voltage times current, which then can be multiplied by time to find energy. $10V\times10A\times36000s$
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